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Edited December 27, 2023
at 10:44 AM
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Max Tool [maxtool.com] has
Milwaukee 2846-21HO M18 18V TOP-OFF 175W Power Supply with an
M18 HO XC6.0 Battery for $130.50 after discount code:
2020more. Shipping is free on $199+ orders, otherwise $8.95.
Comes with an M18 HO XC6.0 Battery which uses newer 21700 battery cells.
M18 TOP-OFF 175W Power Supply & M18 REDLITHIUM HIGH OUTPUT XC6.0 Battery Pack set delivers faster simultaneous power to personal devices and small electronics.
- Attach this portable power supply to any M18 battery (M18 REDLITHIUM HIGH OUTPUT XC6.0 Battery included) to provide continuous power or recharge devices with (1) AC 120V outlet, (1) USB-C PD port, and (1) USB-A port.
- You can quickly charge up to three devices at once, without the barriers of speed throttling.
- With the USB-C PD port (45W), this battery inverter can recharge devices from a fully depleted state to 80% capacity, up to 75% faster than conventional wall chargers (5W).
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Only limited by the battery you're using, or the number of batteries you have.
The USB-C output is going to be the most efficient, I believe, since it's not converting from DC to AC. It's only changing voltage really, DC to DC.
Converting to AC you'll have some losses. As far as the shitty sine wave, anything with its own power supply should be fine (e.g. router).
Consider the M18 12.0 HO battery. It has 216Wh of full charge. So, 216W for one hour. Or, 21.6W for 10 hours, for example. Say your router uses 21.6W --> the M18 12.0 battery should be able to run it for 10 hours. However, the inverter is not going to be 100% efficient. Neither is the power supply of the router going to be 100% efficient.
Say you lose 30% between the DC to AC conversion and the router power supply. 216Wh --> 0.70 = ~150Wh. If the router uses 20W --> 7.5 hours, under ideal conditions.
(Please, anyone, correct me if I'm wrong or have missed something).
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It is pretty cool, and handy. Especially with a 6.0 HO battery included! I have one, and like it. Just keep in mind the AC output is a really sh*tty modified sine wave.
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Cameras, go pro, small lunch box heater, cell phones, during blackouts, charge laptop on job site.
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Anything you can think of, really, that doesn't exceed 175W.
Only limited by the battery you're using, or the number of batteries you have.
The USB-C output is going to be the most efficient, I believe, since it's not converting from DC to AC. It's only changing voltage really, DC to DC.
Converting to AC you'll have some losses. As far as the shitty sine wave, anything with its own power supply should be fine (e.g. router).
Consider the M18 12.0 HO battery. It has 216Wh of full charge. So, 216W for one hour. Or, 21.6W for 10 hours, for example. Say your router uses 21.6W --> the M18 12.0 battery should be able to run it for 10 hours. However, the inverter is not going to be 100% efficient. Neither is the power supply of the router going to be 100% efficient.
Say you lose 30% between the DC to AC conversion and the router power supply. 216Wh --> 0.70 = ~150Wh. If the router uses 20W --> 7.5 hours, under ideal conditions.
(Please, anyone, correct me if I'm wrong or have missed something).