Joined Aug 2010
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Forum Thread
When rounding to two decimal places...
July 22, 2012 at
06:51 PM
in
Question
What would you round 5.3345 to?
I say 5.33 but someone else says 5.34. The complete answer to the problem changes a good amount for the different values. Anyone know the exact rules to rounding in this situation?
I say 5.33 but someone else says 5.34. The complete answer to the problem changes a good amount for the different values. Anyone know the exact rules to rounding in this situation?
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1) Round 5.3345 to 3 decimal places. (answer = 5.335)
2) Take your answer from 1 and round it to two decimal places. (answer = 5.34)
3) Why are the answers not the same?
agreed
Peter Gibbons: [Explaining the plan] Alright so when the sub routine compounds the interest is uses all these extra decimal places that just get rounded off. So we simplified the whole thing, we rounded them all down, drop the remainder into an account we opened.
Joanna: [Confused] So you're stealing?
Peter Gibbons: Ah no, you don't understand. It's very complicated. It's uh it's aggregate, so I'm talking about fractions of a penny here. And over time they add up to a lot.
Joanna: Oh okay. So you're gonna be making a lot of money, right?
Peter Gibbons: Yeah.
Joanna: Right. It's not yours?
Peter Gibbons: Well it becomes ours.
Joanna: How is that not stealing?
Peter Gibbons: [pauses] I don't think I'm explaining this very well.
Joanna: Okay.
Peter Gibbons: Um... the 7-11. You take a penny from the tray, right?
Joanna: From the cripple children?
Peter Gibbons: No that's the jar. I'm talking about the tray. You know the pennies that are for everybody?
Joanna: Oh for everybody. Okay.
Peter Gibbons: Well those are whole pennies, right? I'm just talking about fractions of a penny here. But we do it from a much bigger tray and we do it a couple a million times.
Check it out:
5.33 - 5.3345 = abs value .0045
5.34 - 5.3345 = .0055
Hence, 5.33 is a better approximation because it's closer to 5.3345
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Check it out:
5.33 - 5.3345 = abs value .0045
5.34 - 5.3345 = .0055
Hence, 5.33 is a better approximation because it's closer to 5.3345
I just though that Burninator nailed it where you had a hard time. You never once said it's an approximation!
Don't hate!
A round number is mathematically defined as the product of a considerable number of comparatively small factors[1] as compared to its neighbouring numbers, such as 24 = 2*2*2*3 (4 factors, as opposed to 3 factors for 27; 2 factors for 21, 22, 25, and 26; and 1 factor for 23).
However, a round number is informally considered to be an integer that ends with one or more zeroes (0), such as 1,000, 1,500,000, etc., and a number ending in 5 might be considered in a way more "round" than one ending in neither 0 nor 5. Even a non-integer such as 2.5 might be seen as more round than, say, 2.497 (especially if written as 2.500).
When a quantity is known only to a low precision, a calculation that gives a non-round number is oftentimes rounded in order to avoid giving a false impression of accuracy.
An approximation is a representation of something that is not exact, but still close enough to be useful. Although approximation is most often applied to numbers, it is also frequently applied to such things as mathematical functions, shapes, and physical laws.
Approximations may be used because incomplete information prevents use of exact representations. Many problems in physics are either too complex to solve analytically, or impossible to solve using the available analytical tools. Thus, even when the exact representation is known, an approximation may yield a sufficiently accurate solution while reducing the complexity of the problem significantly.
For instance, physicists often approximate the shape of the Earth as a sphere even though more accurate representations are possible, because many physical behaviours — e.g. gravity — are much easier to calculate for a sphere than for other shapes.
It is difficult to exactly analyze the motion of several planets orbiting a star, for example, due to the complex interactions of the planets' gravitational effects on each other, so an approximate solution is effected by performing iterations. In the first iteration, the planets' gravitational interactions are ignored, and the star is assumed to be fixed. If a more precise solution is desired, another iteration is then performed, using the positions and motions of the planets as identified in the first iteration, but adding a first-order gravity interaction from each planet on the others. This process may be repeated until a satisfactorily precise solution is obtained. The use of perturbations to correct for the errors can yield more accurate solutions. Simulations of the motions of the planets and the star also yields more accurate solutions.
Check it out:
5.33 - 5.3345 = abs value .0045
5.34 - 5.3345 = .0055
Hence, 5.33 is a better approximation because it's closer to 5.3345
This really isnt rocket science here. Simple rounding that we learn in grade school. Problem is, some people adding steps. "Well this number way past the point that we want to round to is higher than 5 so we round up, which in turn changes this number that is way past the point we are rounding to is now higher than 5 so we round up....."
News flash: 4.344999999999 rounded to the hundredths place is still 4.34
I just though that Burninator nailed it where you had a hard time. You never once said it's an approximation!
Don't hate!
A round number is mathematically defined as the product of a considerable number of comparatively small factors[1] as compared to its neighbouring numbers, such as 24 = 2*2*2*3 (4 factors, as opposed to 3 factors for 27; 2 factors for 21, 22, 25, and 26; and 1 factor for 23).
However, a round number is informally considered to be an integer that ends with one or more zeroes (0), such as 1,000, 1,500,000, etc., and a number ending in 5 might be considered in a way more "round" than one ending in neither 0 nor 5. Even a non-integer such as 2.5 might be seen as more round than, say, 2.497 (especially if written as 2.500).
When a quantity is known only to a low precision, a calculation that gives a non-round number is oftentimes rounded in order to avoid giving a false impression of accuracy.
An approximation is a representation of something that is not exact, but still close enough to be useful. Although approximation is most often applied to numbers, it is also frequently applied to such things as mathematical functions, shapes, and physical laws.
Approximations may be used because incomplete information prevents use of exact representations. Many problems in physics are either too complex to solve analytically, or impossible to solve using the available analytical tools. Thus, even when the exact representation is known, an approximation may yield a sufficiently accurate solution while reducing the complexity of the problem significantly.
For instance, physicists often approximate the shape of the Earth as a sphere even though more accurate representations are possible, because many physical behaviours — e.g. gravity — are much easier to calculate for a sphere than for other shapes.
It is difficult to exactly analyze the motion of several planets orbiting a star, for example, due to the complex interactions of the planets' gravitational effects on each other, so an approximate solution is effected by performing iterations. In the first iteration, the planets' gravitational interactions are ignored, and the star is assumed to be fixed. If a more precise solution is desired, another iteration is then performed, using the positions and motions of the planets as identified in the first iteration, but adding a first-order gravity interaction from each planet on the others. This process may be repeated until a satisfactorily precise solution is obtained. The use of perturbations to correct for the errors can yield more accurate solutions. Simulations of the motions of the planets and the star also yields more accurate solutions.
A number that is rounded off is an approximation. I didn't realize that you didn't know that. Sorry about that. I'll try to write future posts in language that you are capable of understanding.
And, for the record, nothing in Burninator's post even referred to my posts. His post was completely accurate and it did not conflict with any of the information that I had posted.
5.3345 rounded to the second decimal equals 5.33
5.3345 rounded to the third decimal equals 5.335
5.335 rounded to the second decimal equals 5.34
* This post was made possible by Math.
5.3345 rounded to two decimal points equals 5.33
5.3345 rounded to three decimal points equals 5.335.
5.335 rounded to two decimal points equals 5.34
But, I'm sure that you have already figured that out by now. So, unless you want to discuss a different issue, I am done explaining this to you.
And, for the record, nothing in Burninator's post even referred to my posts. His post was completely accurate and it did not conflict with any of the information that I had posted.
This really isnt rocket science here. Simple rounding that we learn in grade school. Problem is, some people adding steps. "Well this number way past the point that we want to round to is higher than 5 so we round up, which in turn changes this number that is way past the point we are rounding to is now higher than 5 so we round up....."
News flash: 4.344999999999 rounded to the hundredths place is still 4.34
Sometimes people get lost in the detail. I always like to consider the practical side of problem solving.
Plus it's always been easier for me to visualize a solution first before solving it analytically.
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My quotes just prove my point.
I did not say :
5.3345 = 5.33
I said
5.3345 rounded to the second decimal equals 5.33
This is a true statement.
I give up. I guess you'll never understand but that's okay.